Math, asked by Itzkillerqueen, 5 months ago

pls help
f x = 33 is solution of the equations 2x – y = 54, then find the

value of y

3 Sahil’ s age is 3 years more than half of the Salman’ s age. Frame the

equation.

4 3x + 5y = 9 and 5x + 3y = 7 . Find the value of x + y

5 Write any 4 linear equations in two variables using x and y

Q.2. Solve the following

1. Solve by equating co-efficient x+ y = 4 ; 2x– 5y = 1

2. The sum of the ages of Priyanka and Deepika is 34 years. Priyanka is

elder to Deepika by 6 years. Then find their presentage.

3. Solve by equating coefficient 2y – x = 0 ; 10x+ 15y = 105
find answers of these please request hai guys ​

Answers

Answered by abhisheksinghr81
3

Answer:

Here, Q)=In this question, value of y is 11.

Q3.)Here, The equation formed is x-2y=3.

Q4.)=Here, The value of x+y is 2.

Q5.)=Equations are in explanation.

Q2.)=Solve the following:

Q1.)=Here, Thavalue of x is 3 and y is 1.

Q2.)=Here, The age of Priyanka is 20 years and Deepika is of 14 years.

Q3.)=Here, The value of x is 6 and y is 3.

Step-by-step explanation:

Q)=Here, As per our given question,

=p(x)=2x-y=54

And x=33 is a solution of it,

So, by putting value of x in the equation, we get,

=2×(33)-y=54

=66-y=54

=(-y)=54-66

=(-y)=(-11)

=y=11 (As both sides are equal and have same sign of -)

Q3.)=Here, As given in question,

Let the age of Sahil be x

Let the age of Salman be y

Now, Equation=1/2x=3+y

=x=3+2y

=x-2y=3 (Answer).

Q4.)=Here, As per our given question,

=3x+5y=9 -(1st)eq.

=5x+3y=7 -(2nd)eq.

On solving both equations by elimination method, we have to multiply with 3 in eq1 and with 5 in eq. 2,and then subtract 2nd eq. from 1st eq., we get,

= 9x +15y= 27

=-25x-15=-35

After soving, we get,

=9x-25x=27-35

=(-16x)=(-8)

=16x=8

=x=8/16

=x=1/2

Now, by putting the value of x in eq. 1,we get,

=3×(1/2)+5y=9

=3/2+5y=9

=5y=9-3/2

=5y=(18-3)/2 (After taking Lcm and solving it)

=5y=15/2

=y=15/2/5

=y=3/2

Now, As asked in question,

=x+y=

=1/2+3/2

=(1+3)/2 (As denominators are same)

=4/2

=2

So, x+y =2 (Answer).

Q5.)=Four linear equations are,

=15x+22y=37 -(1)

=14x-13y=23 -(2)

=2x+y=0 -(3)

=x+y=45 -(4)

Q2.)=Solve the following:

Q1.)=Here, As per our given question,

=x+y=4 -(1st)eq.

=2x-5y=1 -(2nd)eq.

Now, As on solving both equations by elimination method, we have to multiply with 5y in eq. 1 and with 1 in eq. 2 and then add both equations,

=5x+5y=20

=2x-5y=1

After solving, we get,

=5x+2x=20+1

=7x=21

=x=21/7

=x=3

By putting the value of x in eq. 1,we get,

=3+y=4

=y=4-3

=y=1 (Answer).

Q2.Here, As in this question,

Let the age of Priyanka be x

Let the age of Deepika be y

Now, x+y=34 -(1st)eq.

Now, x-y=6 -(2nd)eq.

Now, As solving both equations by elimination method, we will add both equations,

=x+y=34

=x-y=6

After solving, we get,

=x+x=34+6

=2x=40

=x=40/2

=x=20

Now, by putting the value of x in eq. 1,we get,

=20+y=34

=y=34-20

=y=14

Hence, Present age of Priyanka is 20 years and of Deepika is 14years.

Q3.)=Here, As given in question,

=2y-x=0

=(-x)+2y=0 -(1st)eq. [Standard form]

Now, 10x+15y=105

=2x+3y=21 -(2nd)eq. (As all numbers are divisible by 5)

Now, On solving both equations by elimination method, we will multiply with 2 in eq. 1 and with 1 in eq. 2 and the add both of them,

=(-2x)+4y=0

=(+2x)+3y=21

After solving it, we get,

=4y+3y=0+21

=7y=21

=y=21/7

=y=3

Now, by putting the value of y in eq. 1,we get,

=(-x)+2×(3)=0

=(-x)=(-6)

=x=6 (As both sides are equal and have same sign of -)

So, The value of x is 6 and y=3 in the given question.

Thank you.

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