Question

pls help fast!!!!!¡!!!!!!!!!!!!!!

Answer 1

hey mate here is your answer:

 1/a+b+x  = 1/a + 1/b + 1/c

1/a+b+x = bx+ax+ab/abx

abx = 3abx + a2x +b2x + a2b+ab2

x2 ( a+b) + x( a2 + b2 +2ab ) + ab( a+b) =0

x2 ( a+b) + x(a+b)2 + a2b+ ab2 = 0

D = b2 - 4ac

= (a+b)4 - 4 ( a+b) ( a2b+ab2 ) 

= a4 + b4 + 4a3b + 4ab3 + 6a2b2 - 4a3b - 4ab3 - 8a2b2

= a4 + b4 - 2a2b2

= (a2 - b2)2

x = -(a+b)2   (+or -) root of  (a2-b2)2 / 2(a+b)

 = -a2 - b2 -2ab +a2 -b2/a(a+b)

 = -2b2 - 2ab/2(a+b)

 = -2b(a+b)/2(a+b) 

 = -b

similarly the other root is -a


I hope this will help you