Question

Pls help..
Find roots of √3cot^2theta-4cot theta+√3

Answer 1

Answer:

Step-by-step explanation:

In pic

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I hope, it helped.

Answer 2

Solution :-

Using A in Place of Theta.

√3 cot²A - 4 CotA + √3

=> √3 Cot²A - (3 CotA + CotA) + √3

=> √3 cot²A - 3 Cot A - CotA + √3

=> √3 CotA ( CotA - √3) -1 ( CotA - √3)

=> (√3 CotA - 1) ( CotA - √3)

=> √3 CotA -1 = 0. & CotA - √3 = 0

=> CotA = 1 / √3. & CotA = √3.

Hence,

The Roots are 1/√3 & √3.