# pls help guys
ABCD is a diameter of a circle of radius 6 cm such that AB=BC=CD. Semicircles are drawn on AB and BD as diameter, as shown in the given attachment. Find the area of shaded region.
# want full solution....
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Area of AB as diameter semi circle = pie ( AB/2)^2/2
As AB + BC = AC = radius = 6
AB = BC
2AB = 6
AB= 3
So Area = pie ( 3/2)^2 /2= pie × 9/8
Area of BD as diameter circle
Now BC is it radius which is AB
So Area = pie ( 3)^2/2 = 9/2 Pie
Area of Ad as diameter semicircle = pie ( 6)^2/2
= 18 pie
So area of shaded = 18 pie - 9/2 pie + 9/8 pie
= 144 pie - 36 pie + 9 pie )/8
= 117 pie/8 = 45.92
As AB + BC = AC = radius = 6
AB = BC
2AB = 6
AB= 3
So Area = pie ( 3/2)^2 /2= pie × 9/8
Area of BD as diameter circle
Now BC is it radius which is AB
So Area = pie ( 3)^2/2 = 9/2 Pie
Area of Ad as diameter semicircle = pie ( 6)^2/2
= 18 pie
So area of shaded = 18 pie - 9/2 pie + 9/8 pie
= 144 pie - 36 pie + 9 pie )/8
= 117 pie/8 = 45.92
tiyamittal1234:
thanks
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