pls help guys very important
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angle XAT = angle OGX = 64 (alt angles of II sides TA and GO)
angle TXA = 90 (diagonals bisect at right angles)
In Trianle TXA, 64 + 90 + angle OTA = 180 (Angle Sum Property)
abngle OTA = 180 - 154
= 26
Hope this helps
Mark as brainliest
angle TXA = 90 (diagonals bisect at right angles)
In Trianle TXA, 64 + 90 + angle OTA = 180 (Angle Sum Property)
abngle OTA = 180 - 154
= 26
Hope this helps
Mark as brainliest
smritijha7298:
pls
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Hello,
As we know that in a square, diagonals intersection angle is 90°. (Given)
Also GXT + AXT = 180°. (Linear Pair)
Therefore GXT = 90°
Similarly AXO = OXG = GXT = AXT = 90°.
Next,
Take a look at Angle G.
64° + y = 90°. (All angles in square are 90°)
Therefore y = 26°. (Assume angle y beside 64)
Next in the pic.
Hope you find my answer useful and hope you mark my answer as brainliest !
Do contact me if needed
@YHarith #YHarith
As we know that in a square, diagonals intersection angle is 90°. (Given)
Also GXT + AXT = 180°. (Linear Pair)
Therefore GXT = 90°
Similarly AXO = OXG = GXT = AXT = 90°.
Next,
Take a look at Angle G.
64° + y = 90°. (All angles in square are 90°)
Therefore y = 26°. (Assume angle y beside 64)
Next in the pic.
Hope you find my answer useful and hope you mark my answer as brainliest !
Do contact me if needed
@YHarith #YHarith
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