Question

PLS HELP I HAVE ASSIGNMENT TO SUBMIT

Answer 1

Explanation:

We need to solve the first parallel circuits then add all series.

so,

$= 3 + ( \frac{1}{6} + \frac{1}{6} ) \\ 3 + \frac{1}{3} \\ \\ = \frac{10}{3} - - - - (1)$

$= 9 + ( \frac{1}{4} + \frac{1}{12} ) \\ = 9 + \frac{1}{3} \\ = \frac{19}{3} - - - (2)$

now solve the equation (1) and (2) as they are in parallel connection

so We get,

$\frac{3}{10} + \frac{3}{19} \\ = \frac{87}{190}$

now solve it with series charge

$= \frac{87}{190} + 2 \\ = \frac{467}{190}$

$2.45 \: ohm$

now by formula

V= I R

v/R = I

18/2.57 =I

i = 7 ampere