Question

pls help i need it urgently
I will mark as brainliest

Answer 1

Answer:

please mark me brainliest

In quadrilateral ABCD

∠C=100°, ∠D=60°

∠A+∠B+∠C+∠D=360°

(Angle sum property of a quadrilateral)

∴∠A+∠B=360°−(100°+60°)

= 360°−160°=200°

But AP and BP are the bisectors of ∠A and ∠B.

∴1/2(∠A+∠B)=1/2×200°=100°

i.e. ∠PAB+∠PBA=100°

But in ΔAPB,

∠PAB+∠PBA+∠APB=180°

⇒100°+∠APB=180°

∠APB=180°−100°=80°

Thus, ∠APB=80°

Answer 2

Sorry I can't help

Next time I will help you sure.

OK mate .

Be happy

Have a nice day .