Math, asked by Vanshithadesikan, 9 months ago

pls help immediately..​

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Answered by vinayak6540
1

Step-by-step explanation:

sum of n terms = 3n^2-2n+4

a1

= let n=1

3(1)^2-2(1)+4

= 3-2+4

=5=a1

a2

= let n=2

3(2)^2-2(2)+4

= 8-4+4

=8=a2

d = a2-a1

= 8-5

=3

11th term

= a+10d

=5+10(3)

=5+30

=35

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