PLs help in question 7 and 8
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7.
p(x)= 4x³+16x²-23x-5x
and
f(x) = 2x-3
g(x)= 2x-3= 0
=> 2x =3
=>x = 3/2
now,
as we know if f(x) is the factor of p(x) then its remainder will be zero.
so,
p(3/2) = 4(3/2)³ + 16(3/2)² -23(3/2)-5(3/2)
= (27/2) + 12 -(69/2) -(15/2)
= (27 +24 -69 -15)/2
= -33/2
hence, its remainder is (-33/2).therefore its not the factor of p(x).
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Answer:
Substitute x=3/2 in the given equation and you can get the answer.
For second.question see the attachment
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