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Answers
Ans .ZnCl , 2150
Answer:
ZnCl₂ . 2H₂O
Step by step Explanation:
Here are the steps of finding the formula of the hydrated compound:
Step 1: Let us pick 100g sample of the hydrated zinc and use it to calculate the formula
a) Mass of ZnCl₂ = 79.12 % of 100g
79.12/100 × 100 g = 79.12g
b) Mass of H₂O
% weight of H₂O = 100% - 79.12%
= 20.88%
20.88% of 100g of the zinc hydrate
20.88/100 × 100g = 20.88g
Step 2: Find the moles of both the ZnCl₂ and the H₂O
Moles = mass / molar mass
a) Moles of ZnCl₂
Molar mass of ZnCl₂ = 136.4g/mol
Moles = 79.12g / 136.4gmol⁻¹
= 0.58 moles
b) Moles of H₂O
Molar mass = 18g/mol
Moles = 20.88g/ 18gmol⁻¹
= 1.16 moles
Step 3: Find the whole number ratio of the moles of the two compounds by divinding both moles with the moles of the ZnCl₂:
ZnCl₂ : H₂O
0.58 : 1.16
0.58/0.58 : 1.16/0.58
1 : 2
ZnCl₂ = 1
H₂O = 2
Therefore the formula of the hydrate:
ZnCl₂ . 2H₂O