Question

pls help
in this question​

Answer 1

Given:

AB||DE

∠BAE = 35*

∠CDE = 53*

As AB||DE, we know that AE is a transversal

Thus, by alternate interior angles, ∠BAE = ∠AED

∠AED = 35*

Also, we know that ∠CDE = 53*

Now, using angle sum property

180* = ∠AED + ∠CDE + ∠DCE

180* = 35* + 53* + ∠DCE

∠DCE = 180* - 35* - 53*

∠DCE = 92

Now, ∠DCE and ∠ACD are a linear pair

So,

∠DCE + ∠ACD = 180*

92 + ∠ACD = 180*

∠ACD = 180*- 92*

∠ACD = 88*

Hope this helped!

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