Math, asked by unkown25, 4 months ago

pls help it's exam time going on ​

Attachments:

Answers

Answered by gowdaspoorthy213
1

Answer:

(4Sin60+Cos60/Sin30)(4Cos30-2Sin30)

[4(✓3/2)+(1/2)/(1/2)][4(✓3/2)-2(1/2)]

(2✓3 + 1)(2✓3 - 1)

4×3-1

12-1

11

Answered by nlinthoingambi22
1

Answer:

11

Step-by-step explanation:

since,

  • sin 60* =
  •  \sqrt{3 \2}
  • sin 30* =
  • 1 \2
  • cos 60* =
  • 1 \2
  • cos 30*=
  •  \sqrt{3 \2}
  • Then,
  • (4 sin60  +  cos60 \sin30 ) (4 cos \: 30 - 2sin30)
  • substitute the required values
  • (4 (\sqrt3  \2) + 1 \2 \1 \2)(4( \sqrt3 \2) - 2(1 \2)
  • ((2 \sqrt{3} ) + 1)((2 \sqrt{3)}  - 1
  • (  2  \sqrt{3} ) ^{2}  - 1
  • 12 -1 = 11

Similar questions