Question

pls help it's urgent...​

Answer 1

Answer:

• The Titanium plate will expand by 2.04 × 10⁻³ cm

Given:

1. Initial length (L₀) = 20 cm.
2. Initial temperature (T₀) = 25 °C
3. Coefficient of expansion = 8.5 × 10⁻⁶
4. Final temperature (T) = 37 °C

Explanation:

$\rule{300}{1.5}$

From the formula of linear expansion we know that,

$\bigstar\;\underline{\boxed{\sf \Delta L=L_{o}\;\alpha\;\Delta T}}$

Here,

• ΔL Denotes Increase/Decrease in length.
• L₀ Denotes Initial length.
• α Denotes coefficient of expansion.
• ΔT Denotes Temperature difference.

Solving & Substituting the values,

$\longrightarrow\sf \Delta L=L_{o}\;\alpha\;\bigg(T-T_{o}\bigg)\\\\\\\\\longrightarrow\sf \Delta L=20\times \bigg(8.5\times 10^{-6}\bigg)\times \bigg(37-25\bigg)\\\\\\\\\longrightarrow\sf \Delta L=20\times \bigg(8.5\times 10^{-6}\bigg)\times 12\\\\\\\\\longrightarrow\sf \Delta L=240\times 8.5\times 10^{-12}\\\\\\\\\longrightarrow\sf \Delta L=2040\times 10^{-6}\\\\\\\\\longrightarrow\sf \Delta L=2.04\times 10^{-3}\\\\\\\\\longrightarrow\large{\underline{\boxed{\red{\sf \Delta L=2.04\times 10^{-3}\;cm}}}}$

∴ The Titanium plate will expand by 2.04 × 10⁻³ cm.

$\rule{300}{1.5}$

Answer 2

Answer:

2.04×10-3

Explanation:

is the correct answer