Question

Pls help it’s urgent pla

Answer 1

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } = 98$

Step-by-step explanation:

$x = 5 - 2 \sqrt{6} \\ {x}^{2} + \frac{1}{ {x}^{2} } \\ = {(5 - 2 \sqrt{6}) }^{2} + \frac{1}{ {(5 - 2 \sqrt{6}) }^{2} } \\ = 25 + 24 - 20 \sqrt{6} + \frac{1}{25 + 24 - 20 \sqrt{6} } \\ = 49 - 20 \sqrt{6} + \frac{1}{49 - 20 \sqrt{6} } \\ = \frac{ {(49 - 20 \sqrt{6} ) }^{2} + 1}{49 - 20 \sqrt{6} } \\ = \frac{2401 + 2400 + 1 - 1960 \sqrt{6} }{49 - 20 \sqrt{6} } \\ = \frac{4802 - 1960 \sqrt{6} }{49 - 20 \sqrt{6} } \\ = \frac{98(49 - 20 \sqrt{6}) }{49 - 20 \sqrt{6} } \\ = 98$