Math, asked by unkown25, 3 months ago

pls help it's urgent trigonometry

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Answered by Anonymous

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Answer:

Hey friend (^_^)

Here is your answer :

1-[cos²A/(1+sinA)]=sinA

LHS :

=1-[cos²A/(1+sinA)]

[USING cos²A+sin²A=1]

=1-[(1-sin²A) /(1+sinA)]

[USING a²-b²=(a+b)(a-b) ]

=1-[(1+sinA)×(1-sinA)/(1+sinA)]

=1-(1-sinA)

=1-1+sinA

=sinA

=RHS

HENCE PROVED

HOPE THIS HELPS YOU

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