Question

pls help it's urgent trigonometry​

Answer 1

Answer:

1+ tan^A

Step-by-step explanation:

1+tan^A /1+sec A=(sec^A-1)/1+sec A

=1+(secA-1)+(secA+1)/(1+secA)

=1+secA-1

=secA

=1+tan^A/1+secA=secA