Question

Pls Help its Urgent ! ​

Answer 1

Answer:

x = 1

hope it helps

pls mark as brainliest

Answer 2

Given :

• Equation $\sf \dfrac{x-1}{3} = 1 + \frac{x-2}{4}$

To Find :

• Solve the equation and check the answer

Solution :

$: \implies \tt \: \frac{x - 1}{3} = 1 + \frac{x - 2}{4} \\ \\ \\ : \implies \tt \frac{x - 1}{3} = \frac{1}{1} + \frac{x - 2}{4} \\ \\ \\ : \implies \tt \frac{x - 1}{3} = \frac{4 + x - 2}{4} \\ \\ \\ : \implies \tt \frac{x - 1}{3} = \frac{x + 2}{4} \: \: \: \: \: \:$

➪  Now, let's Crossmultiply the fraction:

$: \implies \tt \: 3(x + 2) = 4(x - 1) \\ \\ \\ : \implies \tt 3x + 6 = 4x - 4 \: \: \: \: \: \: \: \\ \\ \\ : \implies \tt 3x - 4x = - 4 - 6 \: \: \\ \\ \\ : \implies \tt \: \cancel{- }x = \cancel{- }10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \orange{ : \implies \tt \: x = 10 \bigstar} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Verification :

❍Let's substitute the value of 10 instead of x

$\longrightarrow \tt \frac{x - 1}{3} = 1 + \frac{x - 2}{4} \: \: \: \: \\ \\ \\ \longrightarrow \tt \frac{10 - 1}{3} = 1 + \frac{10 - 2}{4} \\ \\ \\ \longrightarrow \tt \cancel \frac{9}{3} = 1 + \cancel\frac{8}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: 3 = 2 + 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \dashrightarrow \tt \: 3 = 3 \bigstar \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

${\huge{ \sf{ \pink{hence \: verified \dag}}}}$