Question

pls help #log #mathematics #class 11 #IIT-JEE ​

Answer 1

Here's the solution to your given problem

Answer 2

Answer:

1

Step-by-step explanation:

3 ^ (2log3 x) - 2x - 3 = 0

now

2log3 x = log3 x²  [ log property ]

3^(log3 x²) = x² [ again log property;  a ^ loga x = x ]

Hence equation is

x² - 2x - 3 = 0

x² - 3x + x - 3 = 0

(x-3)(x+1) = 0

x = 3, as -1 cannot be taken into consideration

Hence, 1 value is satisfying the equation