Question

pls help me and explain​

Answer 1

Answer:

(e)

Explanation:

It's (2E, 4E)-2,4-hexadiene

This is the E, Z configuration of nomenclature of unsaturated compounds.

If groups are on the same side of double or triple bond, we use Z to denote it.

Likewise, if groups are on the opposite sides of double or triple bond we use E to denote it.