Question

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Answer 1

Step-by-step explanation:

Perimeter of a semi-circular park= (πr+2r) meter.

ATP,

πr+2r= 72

$\frac{22}{7} r + 2r = 72$

$\frac{22r + 14r}{7} = 72$

$36r = 72 \times 7$

$36r = 504$

$r = \frac{504}{36}$

$r = 14$

Radius of semi-circular park is 14 meter.

$area \: of \: semi - circular \: park = \frac{1}{2} \times \pi \times {r}^{2} sq.unit$

$= \frac{1}{2} \times \frac{22}{7} \times 14 \times 14 \: \: {m}^{2}$

$= \frac{22}{14} \times 14 \times 14 \: \: {m}^{2}$

$= 22 \times 14 \: \: {m}^{2}$

$=308 \: \: {m}^{2}$

Answer :- Radius of a semi-circular park is 14 meter.

Area of a semi-circular park is 308 sq. meter

Answer 2

Step-by-step explanation:

ATP,

πr+2r= 72

\frac{22}{7} r + 2r = 72

7

22

r+2r=72

\frac{22r + 14r}{7} = 72

7

22r+14r

=72

36r = 72 \times 7 36r=72×7

36r = 50436r=504

r = \frac{504}{36} r=

36

504

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