Question

pls help me Brothers and sisters​

Answer 1

Step-by-step explanation:

greatest number that divides 73 and 95 leaving 7 as remainder in each case =

HCF of (73-7) and (95-7)

= HCF of (66) and (88)

66 = 2×3×11

88 = 2×2×11

(2 & 11 are common in both of the prime factorisation)

so the HCF is 2×11 = 22

hence, 22 is the greatest number that divides 73 and 95 leaving 7 as remainder in each case

Answer 2

AT FIRST, FIND THE ACTUAL NUMBERS THAT ARE DIVISIBLE.

SO,

73‐7=66

95‐7=88

NOW, FIND THE HCF OF THESE TWO NUMBERS.

For 66 and 88 those factors look like this:

Factors for 66: 1, 2, 3, 6, 11, 22, 33, and 66

Factors for 88: 1, 2, 4, 8, 11, 22, 44, and 88

As you can see when you list out the factors of each number, 22 is the greatest number that 66 and 88 divides into.

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