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Through E, draw a line GEF\\AB\\CD.
Now, GE\\AB and EA is the transversal.
Therefore,
angle GEA = angle BAB = 65⁰ [alt. int. angle]
Again, EH\\CD and EC is the transversal.
Therefore,
angle HEC + angle ECD = 180⁰ [co. int. angle]
or, angle HEC + 125⁰ = 180⁰
or, angle HEC = 180⁰ - 125⁰
or, angle HEC = 55⁰
Now, GEH is a straight line.
Therefore,
angle GEA + angle AEC + angle HEC = 180⁰
[straight line]
or, 65⁰ + x⁰ + 55⁰ = 180⁰
or, 120⁰ + x⁰ = 180⁰
or, x⁰ = 180⁰ - 120⁰
or, x⁰ = 60⁰
Therefore, x⁰ = 60⁰.
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