Question

pls help me

factorise:
$a {}^{3 } + 3a {}^{2} b + 3ab {}^{2} + 2b {}^{3}$
i will make the best of it as brainliest​

Answer 1

Step-by-step explanation:

$a {}^{3} + 3a {}^{2}b + 3ab {}^{2} + 2b {}^{3} \\ = a {}^{3} + 3a {}^{2}b + 3ab {}^{2} + b {}^{3} + b {}^{3} \\ = (a + b) {}^{3} + b {}^{3} \\ = (a + b + b)(a + b) {}^{2} + b(a + b) + b {}^{2} \\ = (a + 2b)(a {}^{2} + 2ab + b {}^{2} + ab + b {}^{2} + b {}^{2} \\ = (a + 2b)(a {}^{2} + 3ab + 3b {}^{2})$

plz follow me ❤