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logₓ₊₁2x-1+log₂ₓ₋₁x+1=2
Let logₓ₊₁2x-1=k. Then, 1/logₓ₊₁2x-1= log₂ₓ₋₁x+1= 1/k.
Now,
k+1/k=2
k²+1=2k
k²-2k+1=0
(k-1)²=0
k=1
logₓ₊₁2x-1=1
x+1=2x-1
x=2
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