Question

pls help me I am having Doubt ​

Answer 1

Answer:

Step-by-step explanation:

=  $\frac{a+b+c}{a^-1.b^-1 + b^-1.c^-1 + c^-1.a^-1}$

= $\frac{a+b+c}{1/ab +1/bc +1/ca}$

= $\frac{a+b+c}{(abc^2 + a^2bc + acb^2)/a^2b^2c^2}$

= $\frac{a+b+c}{(abc(c+a+b))/a^2b^2c^2}$

= $\frac{a+b+c}{abc * (a+b+c)/ a^2b^2c^2}$

= $\frac{a+b+c}{(a+b+c)/abc}$                      [AFTER CANCELLING ABC AND A^2B^2C^2]

= $\frac{1}{1/abc}$

=1 * abc

= abc

hence proved

LHS=RHS