pls help me I need Answers of these 5 Question please help me
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Q1.- Since the opposite angles are congruent, if angle A is 60° then angle C is also 60° and also adjacent angles are supplementary therefore angle B is 120° and its opposite angle D will also be 120°.
Q2. 1:2:4:5,
1+2+4+5 =12
First angle - 1/12x360° =30°(since the sum of all the angles of a quadrilateral equal to 360°)
second angle = 2/12x360° = 60°
third angle = 4/12x360° = 120°
fourth angle = 5/12x 360° = 150°
Q3. Since AB II CD, therefore angle ABD = angle BDC( Alternate interior angles)
angle BDC = 55°
Now, angle ADC = angle ADB + angle BDC
= 60° + 55° = 115°
Q4. Since it is a parellologram => 8x = 32
and 7y =28 (alternate interior angles)
then by solving for 8x = 32, we get x = 32/8= 4
and by solving for 7y = 28, we get y = 28/7 = 4.
Pls mark the brainliest!
Q2. 1:2:4:5,
1+2+4+5 =12
First angle - 1/12x360° =30°(since the sum of all the angles of a quadrilateral equal to 360°)
second angle = 2/12x360° = 60°
third angle = 4/12x360° = 120°
fourth angle = 5/12x 360° = 150°
Q3. Since AB II CD, therefore angle ABD = angle BDC( Alternate interior angles)
angle BDC = 55°
Now, angle ADC = angle ADB + angle BDC
= 60° + 55° = 115°
Q4. Since it is a parellologram => 8x = 32
and 7y =28 (alternate interior angles)
then by solving for 8x = 32, we get x = 32/8= 4
and by solving for 7y = 28, we get y = 28/7 = 4.
Pls mark the brainliest!
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