Question

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Answer 1

Sum of adjacent angles of a parallelogram =180°

$\begin{array}{l} \angle \mathrm{A}+\angle \mathrm{B}=180^{\circ} \\ \Rightarrow 2 \angle \mathrm{A}=180^{\circ} \\ \Rightarrow \angle \mathrm{A}=90^{\circ} \\ \text { also, } 90^{\circ}+\angle \mathrm{B}=180^{\circ} \\ \Rightarrow \angle \mathrm{B}=180^{\circ}-90^{\circ}=90^{\circ} \\ \angle \mathrm{A}=\angle \mathrm{C}=90^{\circ} \\ \angle \mathrm{B}=\angle \mathrm{D}=90^{\circ} \end{array}$