Question

pls help me immediately
class 11 maths..

Answer 1

Hola!

This is done using the formula of Sum of Combination of n things

i.e.,

$^{n}C_{0}+^{n}C_{1}+^{n}C_{2}+\: \cdots\cdots\: ^{n}C_{n}= 2^{n}$

We know, $^{n}C_{0}=1$

As per the question,

To find:

$^{10}C_{1}+^{10}C_{2}+\: \cdots\cdots\: ^{10}C_{10}$

Here, n = 10, but $^{10}C_{0}$ was excluded in addition. Hence we subtract it from actual result

$^{10}C_{1}+^{10}C_{2}+\: \cdots\cdots\: ^{10}C_{10} = 2^{10}- 1$

= 1024- 1

= 1023



Let the Option B be Locked.

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