Math, asked by diyam55, 9 months ago

pls help me....

In right ABC. <A = 40º,<B = 90º, BC = 4 cm. What is the radius of circumcircle of triangle ABC? [sin 40º =0.64, cos 40º = 0.76 ,tan 40º =0.84]

1 point

a)3 cm

b)13.5 cm

c)3.125 cm

d)4cm​

Answers

Answered by p383911
0

Answer:

answer for this question is 3.125 cm.

make me as braniliest. please please......

Similar questions