Question

pls help me in solving ​

Answer 1

Step-by-step explanation:

$-y^{2} + 14y -40$       (First we convert it to its standard form)

= $-(y^{2} -14y+40)$         (Splitting the middle terms)

= $-(y^{2} -10y-4y+40)$        (Taking the common terms together)

= $-[(y^{2} -10y)(-4y+40)]$     (Take out the common factors)

=$-[y(y-10)-4(y-10)]$  

= $-(y-4)(y-10)$ (Ans)   [Root of the problem]