pls help me in solving q6 2nd part ...
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to factorize (a²-b²)³ + (b²-c²)³ + (c²-a²)³
use the following conditional identity,
x³+y³+z³ = 3xyz if x+y+z = 0
in the given expression,
x = a² - b² , y = b²- c², z = c² - a²
by adding them, we get
a²-b²+b²-c²+c²-a² = 0
therefore, (a²-b²)³+(b²-c²)³+(c²-a²)³ =>
3 (a²-b²)(b²-c²)(c²-a²) Answer
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