Question

Pls help me in these angles pls.

send photos..
don't type the answers..
write in a book and send me the pic pls.

I have exams from tomorrow​

Answer 1

hope it helps you aman...☺

Answer 2

$\huge{\underline{\underline{Part\:1→}}}$

$\bold{\underline{\underline{Given→}}}$

• $\rm\green{Angle\:1=50°}$
• $\rm\green{Angle\:2=60°}$
• $\rm\green{Angle\:3=x}$

$\bold{\underline{\underline{To\:Find→}}}$

$\rm\purple{→The\:value\:of\:x}$

$\bold{\underline{\underline{Answer→}}}$

According to Angle Sum Property:-

Angle 1 + Angle 2 + Angle 3 + =180°

$\rm\blue{Angle\:1+Angle\:2+x=180°}$

$\rm\blue{→50°+60°+x=180°}$

$\rm\blue{→50°+60°+x=180°}$

$\rm\blue{→x+110=180°}$

$\rm\blue{→x=180°-110°}$

$\rm\blue{→x=70°}$

$\mathrm{\boxed{\boxed{\pink{→x=70°✔}}}}$

$\huge{\underline{\underline{Part\:2→}}}$

Using Angle Sum Property:-

$\rm\color{blue}{Angle\:1+Angle\:2+x=180°}$

$\rm\color{blue}{→60°+90°+x=180°}$

$\rm\color{blue}{→x+150°=180°}$

$\rm\color{blue}{→x=180°-150°}$

$\rm\color{blue}{→x=30°}$

$\mathrm{\boxed{\boxed{\pink{→x=30°✔}}}}$

$\huge{\underline{\underline{Part\:3→}}}$

Using Angle Sum Property:-

$\rm\color{steelblue}{Angle\:1+Angle\:2+x=180°}$

$\rm\color{steelblue}{→30°+110°+x=180°}$

$\rm\color{steelblue}{→x+140°=180°}$

$\rm\color{steelblue}{→x=180°-140°}$

$\rm\color{steelblue}{→x=40°}$

$\mathrm{\boxed{\boxed{\pink{→x=40°✔}}}}$

$\huge{\underline{\underline{Part\:4→}}}$

Using Angle Sum Property:-

$\rm\color{skyblue}{→50°+x+x=180°}$

$\rm\color{skyblue}{→50°+2x=180°}$

$\rm\color{skyblue}{→2x=180°-50°}$

$\rm\color{skyblue}{→2x=130°}$

$\rm\color{skyblue}{→x=\dfrac{130°}{2}}$

$\rm\color{skyblue}{→x=\dfrac{\red{\cancel{\color{skyblue}{130°}}}}{\red{\cancel{\color{skyblue}{2}}}}}$

$\rm\color{skyblue}{→x=65°}$

$\mathrm{\boxed{\boxed{\pink{→x=65°✔}}}}$

$\huge{\underline{\underline{Part\:5→}}}$

Using Angle Sum Property:-

$\rm\purple{Angle\:1+Angle\:2+Angle3=180°}$

$\rm\purple{→x+x+x=180°}$

$\rm\purple{→3x=180°}$

$\rm\purple{→x=\dfrac{180°}{3}}$

$\rm\purple{→x=\dfrac{\color{cyan}{\cancel{\purple{180°}}}}{\color{cyan}{\cancel{\purple{3}}}}}$

$\rm\purple{→x=60°}$

$\mathrm{\boxed{\boxed{\pink{→x=60°✔}}}}$

$\huge{\underline{\underline{Part\:6→}}}$

Using Angle Sum Property:-

$\rm\color{darkblue}{Angle\:1+Angle\:2+Angle3=180°}$

$\rm\color{darkblue}{→90°+2x+x=180°}$

$\rm\color{darkblue}{→90°+3x=180°}$

$\rm\color{darkblue}{→3x=180°-90}$

$\rm\color{darkblue}{→3x=90°}$

$\rm\color{darkblue}{→x=\dfrac{90°}{3}}$

$\rm\color{darkblue}{→x=\dfrac{\red{\cancel{\color{darkblue}{90°}}}}{\red{\cancel{\color{darkblue}{3}}}}}$

$\rm\color{darkblue}{→x=30°}$

$\mathrm{\boxed{\boxed{\pink{→x=30°✔}}}}$

HOPE IT HELPS.