Question

pls help me in this question ​

Answer 1

$\: (i) p(x) = x ^ 2 + x + k \\ \: Finding \: remainder \: when \: x ^ 2 + x + k \: \\ Dividend \: \\ Step \: 1: \: Put \: Divisor \: = 0 \: x - \: 1 = \: 0 x \: = \: 1 \\ \: is \: \\ divided \: by \: x - 1 \: Divisor \\ \: Step \: 2 \: : Let \: \\ p(x) = x ^ 2 + x + k \: \\ Putting \: x \: = 1 p(1)=(1)^ 2 +1+ k =1+1+k$

your answer

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