Math, asked by Btsarmy1202, 3 months ago

Pls help me in this question it's urgent

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Answered by rainha
1

Step-by-step explanation:

Sides of triangular wall are 11m, 6m and 15m

Here a=11, b=6, c=15

s =  \frac{a + b + c}{2}

s =  \frac{11 + 6 + 15}{2}  = 16

area =  \sqrt{s(s - a)(s - b)(s - c)}

area =  \sqrt{16 \times 5 \times 1 0 \times 1}  = 20 \sqrt{2}  {m}^{2}

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