Question

pls help me in thiss​

Answer 1

Given:

• Difference of the squares of two positive integers is 180 the square of the smaller number is 8 times the larger.

To Find:

• the numbers

Solution:

$\bigstar \sf \: now \: let \: the \: small \: number \: be \: x \: \\ \sf \: and \: larger \: number \: be \: y \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

let's frame an equation according to the given statement

$\longmapsto\sf \: {y}^{2} - {x}^{2} = 180$

As given that y is 8 times more than x so, let's take 8x with y

${ : \implies} \sf8 {x}^{2} - {x}^{2} = 180 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ { : \implies} \sf {x}^{2} - 18x + 10x - 180 \: \: \: \: \: \: \\ \\ \\ { : \implies} \sf \: x(x - 18) - 10(x - 18) \: \: \\ \\ \\ { : \implies} \sf(x - 18)(x - 10) \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Now let's take away- 10

$\sf \longrightarrow {y}^{2} = 8 {x} \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {y}^{2} = 8(18) \\ \\ \\ \sf \longrightarrow \: {y}^{2} = 144 \: \: \\ \\ \\ \sf \longrightarrow \: y = \sqrt{144} \\ \\ \\ \bf \longrightarrow \pink{ y = 12 \bigstar}$

Answer 2

Hope it's useful. Mark as the brainliest answer.

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