Pls Help Me
Jitna Aata Hai Utna Hi Dena Par Right Answer Dena Pls :-(
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2
Answer:
Correct option is
B
tan50
∘
k=
cot80
+cot20
3+cot80
cot20
=
cot(90
−10
)+cot(90
−70
)
3+cot(90
−10
)cot(90
−70
)
⇒k=
tan10
+tan70
3+tan10
tan70
⇒k=
sin10
cos70
+cos10
sin70
3cos10
cos70
+sin70
sin10
⇒k=
sin(10
+70
)
3(
2
cos(10
+70
)+cos(10
−70
)
)+(
2
cos(10
−70
)−cos(10
+70
)
)
⇒k=
sin80
2cos60
+cos80
=
sin80
1+cos80
⇒k=
2sin40
cos40
2cos
2
40
=cot40
=tan50
o
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