Question

pls help me , only those who know how to deal this qn only ans​

Answer 1

Answer:

${x}^{2} - 6x + 11 = 0.$

Step-by-step explanation:

${x}^{2} - 2x + 3 = 0 \\ \\ \alpha + \beta = 2 \\ \\ \alpha \beta = 3 \\ \\ \\ \\ s = ( \alpha + 2) + ( \beta + 2) \\ = ( \alpha + \beta ) + 4 \\ \\ = 2 + 4 \\ \\ = 6 \\ \\ \\ p = ( \alpha + 2)( \beta + 2) \\ \\ = ( \alpha \beta + 2( \alpha + \beta ) + 4) \\ \\ = 3 + 2(2) + 4 \\ \\ = 7 + 4 \\ \\ = 11. \\ \\ \\ {x}^{2} - sx + p = 0 \\ \\ {x}^{2} - 6x + 11 = 0.$