Math, asked by mehek1215, 9 months ago

Pls help me out.....​

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Answers

Answered by zoya12515
1

Step-by-step explanation:

here is your answer

please try to solve it yourself

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Answered by johnkumarrr4
0

k=-3/4 or k=3

Step-by-step explanation:

Given,

\left ( k+1 \right )x^{2}-4kx+9=0

D=b^{2}-4ac

a=k+1,b=-4k,c=9

find the value of k

Solution,

D=0 if both roots are real and equal

\left ( -4k \right )^{2}-4\left ( k+1 \right )9=0

16k^{2}-36\left ( k+1 \right )=0

4\left ( 4k^{2} -9\left ( k+1 \right )\right )=0

4k^{2}-9k-9=0

4k^{2}-12k+3k-9=0     (middle term split)

4k\left ( k-3 \right )+3\left ( k-3 \right )=0

\left ( 4k+3 \right )\left ( k-3 \right )=0

4k+3=0

k=-3/4

or

k-3=0

k=3

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