Question

pls help me out in thus this ques, correct ans will mark as brainliest​

Answer 1

Answer:

Step-by-step explanation:

Solution:

Here point Q lie on y-axis. So its abscissa will be zero. Let its distance from origin is k along y -axis. So its co-ordinate will be:

Co-ordinate of Q = (0 , k)       ...1)

 OQ = k  unit

Co-ordinate of P = (√13,0)

OP = √13    unit

PQ = 7    unit             (Given)  

We see that in  Δ POQ :

∠QOP = 90°

So  Δ POQ  is a right angle triangle, by Pythagoras' Rule:

OQ² + OP² = PQ²

k² +(√13)² = 7²

k² +13 = 49

k² = 36

So:

k = 6 units

Then Co-ordinate of Q can be obtained by equation 1):

Co-ordinate of Q = (0,6)

therefore the correct answer is option (b)

Answer 2

Step-by-step explanation:

by using Pythagoras theorem

${opp}^{2} + {adj}^{2} = {hyp}^{2}$

${opp }^{2} + { \sqrt{13} }^{2} = {7}^{2}$

${opp}^{2} = 49 - 13$

${opp}^{2} = 36$

$opp = \sqrt{36}$

$opp \: = 6$

therefore Q = (0,6)

which is option (b)

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