Math, asked by sahananeel07, 1 month ago

pls help me out this question
Out of 99 candies divided among A, B, & C, A got 36 candies less than C, who got twice the number of candies got by A & B. Find the number of candies got by B
fastest answer will be the winner

Answers

Answered by anirudhnayakscs80042
0

Answer:

Step-by-step explanation:

A=C-36

A+36=C

Also C=2(A+B)

C=2A+2B

A+36=2A+2B

A+2B=36

Answered by RvChaudharY50
1

Given :- Out of 99 candies divided among A, B, & C, A got 36 candies less than C, who got twice the number of candies got by A & B. Find the number of candies got by B ?

Solution :-

Let C got total x candies .

so,

→ Total candies = 99

→ Candies C got = x

→ Candies A got = (x - 36)

then,

→ Candies B got = 99 - (x + x - 36) = (135 - 2x)

A/q,

→ Candies C got = 2(Candies A got + Candies B got)

→ x = 2[x - 36 + 135 - 2x]

→ x = 2[99 - x]

→ x = 198 - 2x

→ x + 2x = 198

→ 3x = 198

→ x = 66 .

therefore,

→ Candies B got = (135 - 2x) = 135 - 2 * 66 = 135 - 132 = 3 (Ans.)

Hence, the number of candies got by B are 3 .

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