pls help me out this question
Out of 99 candies divided among A, B, & C, A got 36 candies less than C, who got twice the number of candies got by A & B. Find the number of candies got by B
fastest answer will be the winner
Answers
Answer:
Step-by-step explanation:
A=C-36
A+36=C
Also C=2(A+B)
C=2A+2B
A+36=2A+2B
A+2B=36
Given :- Out of 99 candies divided among A, B, & C, A got 36 candies less than C, who got twice the number of candies got by A & B. Find the number of candies got by B ?
Solution :-
Let C got total x candies .
so,
→ Total candies = 99
→ Candies C got = x
→ Candies A got = (x - 36)
then,
→ Candies B got = 99 - (x + x - 36) = (135 - 2x)
A/q,
→ Candies C got = 2(Candies A got + Candies B got)
→ x = 2[x - 36 + 135 - 2x]
→ x = 2[99 - x]
→ x = 198 - 2x
→ x + 2x = 198
→ 3x = 198
→ x = 66 .
therefore,
→ Candies B got = (135 - 2x) = 135 - 2 * 66 = 135 - 132 = 3 (Ans.)
Hence, the number of candies got by B are 3 .
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