Question

Pls help me out with this answer$\frac{\sqrt[3]{\sqrt[2]{9+\sqrt{25} } }\\}{10^{2} }$

Answer 1

Step-by-step explanation:

$\begin{gathered}\frac{\sqrt[3]{\sqrt[2]{9+\sqrt{25} } }}{10^{2} }\end{gathered}$

$= \begin{gathered}\frac{\sqrt[3]{\sqrt[2]{9+5} }}{10^{2} }\end{gathered}$

$= \begin{gathered}\frac{\sqrt[3]{\sqrt[2]{14} }}{10^{2} }\end{gathered}$

$\\ = \frac{ {14}^{ \frac{1 \times 1}{2 \times 3} } }{ {10}^{2} }$

$\\ = \frac{ \sqrt[2 \times 3]{14} }{ {10}^{2} }$

$\\ \boxed{\red{ = \frac{ \sqrt[6]{14} }{100} }}$