Question

Pls help me out with this question

Answer 1

Answer:

13.33 m/sec

Explanation:

Let the total distance be 2x m

Time taken for first x meters is

$\frac{x}{10} \: secs$

Time taken for next x meters is

$\frac{x}{20} \: secs$

Average velocity is

$\frac{10 \times \frac{x}{10} + 20 \times \frac{x}{20} }{ \frac{x}{10} + \frac{x}{20} }$

$= \frac{2x}{ \frac{3x}{20} } = \frac{40}{3} = 13.33$

Answer 2

Answer:

13.33 m/s

Explanation:

The formula to find avg. velocity is

Vavg=2×v1×v2/v1+v2

where, v1 is velocity of train for distance1 and v2 is velocity for distance2.

Now,

Vavg=2×10×20/10+20

=400/30

=13.33 m/sec