Physics, asked by 00252618690281, 11 months ago

Pls help me please!!!!!

A floppy disk in a commuter rotates from test to an angular velocity of 3.14 rad/sec in a time of 0.8 sec.
(a) what is the angular acceleration?
(b) what is the angle that the disk rotates in coming to this velocity?

Answers

Answered by Martin84
1

Explanation:

 \omega = 3.4 \frac{rad}{s}  \\ time \:  = 0.8s \\ \omega1 = 0 \\ we \: \omega = 3.4 know \: that \\  \omega  = \omega1 +  \alpha t \\  \alpha  =  \frac{ \omega}{time}  =  \frac{3.4}{0.8}  =  \frac{17}{}  \frac{rad}{ {s}^{2} }  \\  \omega  =   \frac{\theta \: }{t}  \\ \theta =  \omega \times t = 0.8 \times 3.4 = 2.75 rdian

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