Math, asked by harry542980, 8 months ago

pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls help me pls ​

Attachments:

Answers

Answered by Mihir1001
15
6.
( \sqrt{7} - \sqrt{6} )(3 \sqrt{7} - 2 \sqrt{6} )

 = ( \sqrt{7} )(3 \sqrt{7} ) + ( \sqrt{7} )( - 2 \sqrt{6} ) + ( - 6)(3 \sqrt{7} ) + ( - \sqrt{6} )( - 2 \sqrt{6} )

 = 21 - 2 \sqrt{42} - 3 \sqrt{42} + 12

 = 33 - 5 \sqrt{42}
..
..
..
..


7.

 {a}^{n} + {a}^{x}

None
Answered by vidhyasoms2
1

Answer:

Step-by-step explanation:

6.

( \sqrt{7} - \sqrt{6} )(3 \sqrt{7} - 2 \sqrt{6} )

= ( \sqrt{7} )(3 \sqrt{7} ) + ( \sqrt{7} )( - 2 \sqrt{6} ) + ( - 6)(3 \sqrt{7} ) + ( - \sqrt{6} )( - 2 \sqrt{6} )

= 21 - 2 \sqrt{42} - 3 \sqrt{42} + 12

= 33 - 5 \sqrt{42}  

..

..

..

..

7.

{a}^{n} + {a}^{x}  

None

Similar questions