Question

pls help me pls pls pls​

Answer 1

$\boxed{QUESTION:-}$

If Sec∅+Tan∅=p

then, Prove $\frac{p^2 - 1}{2p}$

A=∅

$\boxed{Solution:-}$

Put the Value of p in the Equation↓

→ $\frac{(SecA+TanA)^2 -1}{2×SecA+TanA}$

=>Sec²A+Tan²A+2SecATanA-1 ←Upper Fraction,[Note→Sec²A+Tan²A=1]

=>2SecATanA ←Lower Fraction

→$\frac{1-1+(2SecATanA)}{2SecATanA}$

→$\frac{\cancel{2SecATanA}}{\cancel{2SecATanA}}$=1

$\mathcal{BE \: BRAINLY}$