Math, asked by komal2895, 10 months ago

pls help me regarding this question....​

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Answered by saibalajipolymers99
0

Answer:

ok

Step-by-step explanation:

Answered by sapnashu13
1

Answer:

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we get

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we geta=4; b=-8k and c=-9.

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we geta=4; b=-8k and c=-9.Since one root is the negative of the other, let us assume that the roots are p an -p.

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we geta=4; b=-8k and c=-9.Since one root is the negative of the other, let us assume that the roots are p an -p.Sum of the roots, a+(-a)=-b/a= - (-8k) / 4

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we geta=4; b=-8k and c=-9.Since one root is the negative of the other, let us assume that the roots are p an -p.Sum of the roots, a+(-a)=-b/a= - (-8k) / 40=2k

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we geta=4; b=-8k and c=-9.Since one root is the negative of the other, let us assume that the roots are p an -p.Sum of the roots, a+(-a)=-b/a= - (-8k) / 40=2kk=0

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