Question

pls help me solve question 7

Answer 1

❤Here is your solutions❤

Given :-

Circumference of outer circle = 194.68 m

Let the radius of outer circle be R

=>2πR = 194.68 m
=>2 × 3.14 R = 194.68 m
=>R=31m
=>Radius of inner circle (r) = Radius of outer circle – width

= 31 m – 6 m
Radius of inner circle = 25 m

area of track = area of outer circle – Area of inner circle

=> πR²– πr²
=> π (R²- r²)
=>22/7 (32^2 - 25^2)
=>1056m²

Now

cost of leveling 1 m^2 = 25 paise = Rs 0.25

Hence

cost of leveling track = Rs 0.25 × 1056 = Rs 264

hope it helps you

Answer 2

$\textbf{\huge{ANSWER:}}$

Given:

Circumference = 194.68 m

Let radius = R

$2\pi R = 194.68$

Solving it further,

2 × 3.14 × R = 194.68 ( As here we have the result in decimals, thus, to simplify our calculation, we will take the value of pie as = 3.14 )

=》 R = 31 m ( I've written the answer directly without any calculation to make the answer simple )

Radius of inner circle = Radius of outer circle - The Given Width

=》 Radius = 31 - 6

=》 Radius = 25 m

So now,

Area of track = Area of outer circle - The Area of the inner circle

=》 $\pi R^{2} - \pi r^{2}$

=》 $\pi ( 32^{2} - 25^{2}$

=》 $\frac{22}{7} × ( 1024 - 625 )$ ( As we have the numbers without decimal, I've taken the value of pie as = 22/7 )

=》 1056 m ^2

Finally:

Cost of levelling 1 m^2 of area = 25 Paise
In rupees = Rs. 0.25

Cost of levelling track = 0.25 × 1056
=》 Cost = Rs. 264

Hope it Helps!! :)