Question

pls help me solve this​

Answer 1

Answer:

Let us understand how to tackle this problem, step by step.

We are given with 24g of O₃ asking the number of atoms present in it.

We know that every mole has Avogadro number of molecules. And every molecule has Avogadro number of atoms. That is, if we are given with 2 molecules of ozone, then the number of atoms would become ( $2\:N_A$ ) atoms.

Now let's first calculate the number of moles of O₃ given.

$\implies \text{No. of moles:} = \dfrac{Given\:Mass}{Molecular\:Mass}\\\\\\\implies \text{Number of moles:} = \dfrac{24\:g}{48\:g}\\\\\\\implies \text{Number of moles:} = \dfrac{1}{2} = 0.5\:\:moles$

$\text{We know that, 1 mole has}\: N_A\: \text{ number of molecules.}\\\text{Also, we are given that}\: O_3\; \text{has 3 atoms of Oxygen.}\\\\\implies \text{Number of molecules} = 0.5 \times 6.022 \times 10^{23}\:molecules\\\\\implies \text{Number of O atoms} = 3\\\\\implies \text{Total number of O atoms} = 3 \times \text{No. of molecules}\\\\\implies \text{ Total number of O atoms} = 3 \times 0.5 \times 6.022 \times 10^{23}\\\\\implies \text{Total number of O atoms} = 9.033 \times 10^{23}\:atoms$

This is the required answer.