Math, asked by jagathireddy83, 4 months ago

pls help me solve this problem

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Answered by tajindersinghrehan71

1

Answer:

$\tan( {65}^{o} ) = \tan( {90}^{o} - {25}^{o} )$

$since \: tan \: (90 - \alpha ) = \cot( \alpha )$

$therefore \: \: \cot( {25}^{o} )$

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