Pls help me solve this question fast. I needed it now pls help
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we have
AB =AC
we can write this
AX +BX=CY+Ay. (I)
as we know that tangent from one point is equal...
therefore
AX=AY.
now we can put in (I) equation
AX+BX=AX+CY. (AX=AY)
now BX=CY. (II)
as we know that tangent from one point is equal to each other therefore.....
BX=BZ and CY =CZ.
now from second equation we get
BZ=CZ.
Hence
BC is bisected at the point of contact.
plz if my answer is helpful for you then please mark as brain liest.
AB =AC
we can write this
AX +BX=CY+Ay. (I)
as we know that tangent from one point is equal...
therefore
AX=AY.
now we can put in (I) equation
AX+BX=AX+CY. (AX=AY)
now BX=CY. (II)
as we know that tangent from one point is equal to each other therefore.....
BX=BZ and CY =CZ.
now from second equation we get
BZ=CZ.
Hence
BC is bisected at the point of contact.
plz if my answer is helpful for you then please mark as brain liest.
SANJU007:
thank you
u r most welcome. dear plz mark me as brain liest
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